How do you solve 7^x = 5?
Isolate the exponential, take logs: x = ln(5)/ln(7) ≈ 0.83 (or x = log_7(5) via change-of-base).
Video Summary
Isolate the exponential term; if two exponentials exist, place one on each side before proceeding.
Take natural log (ln) or common log (log10) of both sides and apply the power rule to move exponents forward.
Use change-of-base or write in logarithmic form when convenient (e.g., x = log_7(5) = ln5/ln7).
Solve algebraically by collecting x-terms, factoring, and dividing when x appears on both sides.
Verify numeric solutions graphically by entering left and right expressions as y1 and y2 and finding their intersection.
Isolate the exponential, take logs: x = ln(5)/ln(7) ≈ 0.83 (or x = log_7(5) via change-of-base).
Either ln or log10 works; choose whichever your calculator has — both allow the power rule and change-of-base.
Take logs of both sides, apply the power rule, expand and collect x-terms, factor x, then divide to isolate x (numeric ≈ 4.01).
Enter the left expression as y1 and the right as y2, adjust the window if needed, and find the x-coordinate of their intersection.
Change-of-base converts log_b(a) into ln(a)/ln(b) (or log10) so you can evaluate logarithms for arbitrary bases on standard calculators.
"We isolate the exponential part, take the logarithm of both sides, and solve for the variable."
The initial approach to solving exponential equations involves isolating the exponential term. If there are two exponential parts, they should be placed on opposite sides of the equation.
Either the common logarithm (base 10) or the natural logarithm (base e) can be used since these are commonly available on calculators.
After applying the logarithm, the next step is to solve for the variable and subsequently check the solutions visually using graphs.
"Taking the natural logarithm allows us to apply the power property to simplify our equation."
For the first example, the goal is to isolate (7^x), resulting in the equation (7^x = 5) after adding one to both sides.
Since it is not possible to change the base to a common number, the natural logarithm is applied to both sides: (\ln(7^x) = \ln(5)).
The power property of logarithms converts the exponent into a coefficient, allowing the equation to be rewritten as (x \cdot \ln(7) = \ln(5)).
Dividing both sides by (\ln(7)) enables us to find that (x) is approximately (0.83).
"Rewriting the equation in a logarithmic form offers another valid pathway to the solution."
An alternative method shown involves rewriting the equation (7^x = 5) in logarithmic form as (\log_7(5) = x).
Utilizing the change of base formula provides the same expression for (x) that was derived earlier: (\frac{\ln(5)}{\ln(7)}).
"Using a graphing calculator, we can verify our solution by finding the intersection point of the two functions."
To confirm the accuracy of the solution, the left side of the original equation is input as (y_1) and the right side as (y_2) into a graphing calculator.
Adjustments to the viewing window may be necessary, and the intersection point's x-coordinate validates the computed value of (x).
"When dealing with two exponential parts, we take logarithms of both sides to balance the equation."
In the next example with two exponential functions, (3 \times 2^x = 15), the exponential part is isolated first.
The logarithm is applied producing (\ln(2^x) = \ln(5)). After simplifying, we find (x) from (\frac{\ln(5)}{\ln(2)}), yielding an approximate result of (2.32).
"Using logarithmic identities helps to manipulate equations involving multiple exponential terms."
When faced with the equation ( \left( \frac{2}{3} \right)^x = 5^{3-x} ), the logarithm is taken on both sides.
This results in a more complex equation where rearranging and factoring allows for solving (x) by combining terms involving (x) and isolating it.
The computed value of (x) is confirmed through graphing the relevant functions.
"Comparing the coefficients of like terms helps to isolate and solve for the variable efficiently."
Another equation involving both sides showcases exponents with terms on one side.
After isolating and balancing the constants versus the variable terms, (x) is determined again by estimating using a graphing calculator.
Verifying with the original equation ensures accuracy, illustrating a hands-on approach for confirming mathematical solutions.